Infinite precision intermediate arithmetic: how much would break?

mathstuf:

!v definitely depends on the bit width. What does one do with !i32::min() otherwise?

!i32::MIN == i32::MAX at every bit width.

mathstuf:

If this is then & or | with a value, there are questions of what width those operations work at.

!, & and | behave the same at every signed bit width, and Python has them on infinite width. The only issue is that ! automatically wraps on unsigned types.