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"path": "/abs/2603.07589v1",
"publishedAt": "2026-03-10T00:00:00.000Z",
"site": "https://arxiv.org",
"tags": [
"Aminadav Chuyoon",
"Amir Shpilka"
],
"textContent": "**Authors:** Aminadav Chuyoon, Amir Shpilka\n\nWe study sparse polynomials with bounded individual degree and their factors, obtaining the following structural and algorithmic results. 1. A deterministic polynomial-time algorithm to find all sparse divisors of a sparse polynomial of bounded individual degree, together with the first upper bound on the number of non-monomial irreducible factors of such polynomials. 2. A $\\mathrm{poly}(n,s^{d\\log \\ell})$-time algorithm that recovers $\\ell$ irreducible $s$-sparse polynomials of individual degree at most $d$ from blackbox access to their (not necessarily sparse) product. This partially resolves a question of Dutta-Sinhababu-Thierauf (RANDOM 2024). In particular, if $\\ell=O(1)$ the algorithm runs in polynomial time. 3. Deterministic algorithms for factoring a product of $s$-sparse polynomials of individual degree $d$ from blackbox access. Over fields of characteristic zero or sufficiently large characteristic the runtime is $\\mathrm{poly}(n,s^{d^3\\log n})$; over arbitrary fields it is $\\mathrm{poly}(n,(d^2)!,s^{d^5\\log n})$. This improves Bhargava-Saraf-Volkovich (JACM 2020), which gives $\\mathrm{poly}(n,s^{d^7\\log n})$ time for a single sparse polynomial. For a single sparse input we obtain $\\mathrm{poly}(n,s^{d^2\\log n})$ time. 4. Given blackbox access to a product of factors of sparse polynomials of bounded individual degree, we give a deterministic polynomial-time algorithm to find all irreducible sparse multiquadratic factors with multiplicities. This generalizes the algorithms of Volkovich (RANDOM 2015, 2017) and extends the complete-power test of Bisht-Volkovich (CC 2025). To handle arbitrary fields we introduce a notion of primitive divisors that removes characteristic assumptions from most of our algorithms.",
"title": "On Factorization of Sparse Polynomials of Bounded Individual Degree"
}